Last week I think I tripped a few of you up…Congrats to still unreal for getting the right answers.

sin θ = Opposite over Hypotenuse = Y/X

cos θ = Adjacent over Hypotenuse = Z/X

tan θ = Opposite over Adjacent = Y/Z

csc θ = 1/Opposite over Hypotenuse = 1/(Y/X) = X/Y

sec θ = 1/Adjacent over Hypotenuse = 1/(Z/X) = X/Z

cot θ = 1/Opposite over Adjacent = 1/(Y/Z) = Z/Y

This week we will use the same “lopsided” triangle and solve for Z (and before someone points it out) the triangle is NOT to scale!

5 comments to "Math"

  • How would you like this to be part of your entry in Wiki? lol

    Main interests: Metaphysics, Music, Mathematics, Ethics, Politics
    Notable ideas: Musica universalis, Golden ratio, Pythagorean tuning, Pythagorean theorem
    Influences: Thales, Anaximander, Pherecydes
    Influenced: Philolaus, Alcmaeon, Parmenides, Plato, Euclid, Empedocles, Hippasus, Kepler


  • Wiki? Bah, humbug.

    SU - you forgot to show your work (which was a major fault of mine; I almost never did either).

    Given the Pythagorean Theorem, in which the sides a and b and hypotenuse c of a right triangle are related with the formula a^2 + b^2 = c^2, set a to 12, b to Z and c to 13, and solve thusly:

    12^2 + Z^2 = 13^2
    Z^2 = 169 - 144
    (Z^2)^.5 = (25)^.5
    Z = 5

    And I'll take the bonus for not using a calculator :-)

  • Oh, yeah?
    I get a bonus for the quick look up of Mr. Pythagoras, too.

    Show my work???
    How do you not know the Pythagorean Theorem??

  • My wife did the math in her head and talked the whole thing that is bonus points!


    steveegg...thanks for showing your work!


  • That's crap!
    I want a "check+"!
    (see: south park)

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